Base | Representation |
---|---|
bin | 1101011111001… |
… | …10001100010100 |
3 | 21212220010120220 |
4 | 12233212030110 |
5 | 212430444000 |
6 | 15120554340 |
7 | 2542451454 |
oct | 657461424 |
9 | 255803526 |
10 | 113140500 |
11 | 58957150 |
12 | 31a829b0 |
13 | 1a594955 |
14 | 11051d64 |
15 | 9ded1a0 |
hex | 6be6314 |
113140500 has 96 divisors (see below), whose sum is σ = 359468928. Its totient is φ = 27424000.
The previous prime is 113140499. The next prime is 113140501. The reversal of 113140500 is 5041311.
It is an interprime number because it is at equal distance from previous prime (113140499) and next prime (113140501).
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 113140500.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113140501) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 13072 + ... + 19928.
It is an arithmetic number, because the mean of its divisors is an integer number (3744468).
Almost surely, 2113140500 is an apocalyptic number.
113140500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 113140500, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (179734464).
113140500 is an abundant number, since it is smaller than the sum of its proper divisors (246328428).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113140500 is a wasteful number, since it uses less digits than its factorization.
113140500 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6890 (or 6878 counting only the distinct ones).
The product of its (nonzero) digits is 60, while the sum is 15.
The square root of 113140500 is about 10636.7523239004. The cubic root of 113140500 is about 483.6591012964.
Adding to 113140500 its reverse (5041311), we get a palindrome (118181811).
It can be divided in two parts, 1 and 13140500, that added together give a triangular number (13140501 = T5126).
The spelling of 113140500 in words is "one hundred thirteen million, one hundred forty thousand, five hundred".
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