Base | Representation |
---|---|
bin | 1010111011001100010001… |
… | …0000011110001111000100 |
3 | 1120112100010102002221200020 |
4 | 2232303010100132033010 |
5 | 3033301104412241400 |
6 | 41314125114215140 |
7 | 2346561040434060 |
oct | 256630420361704 |
9 | 46470112087606 |
10 | 12012021212100 |
11 | 39112a6904438 |
12 | 14200157244b0 |
13 | 691962070440 |
14 | 2d755635caa0 |
15 | 15c6d84812a0 |
hex | aecc441e3c4 |
12012021212100 has 144 divisors (see below), whose sum is σ = 42775115634048. Its totient is φ = 2534404469760.
The previous prime is 12012021212057. The next prime is 12012021212123. The reversal of 12012021212100 is 121212021021.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 12012021212100.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 219973089 + ... + 220027688.
Almost surely, 212012021212100 is an apocalyptic number.
12012021212100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
12012021212100 is an abundant number, since it is smaller than the sum of its proper divisors (30763094421948).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12012021212100 is a wasteful number, since it uses less digits than its factorization.
12012021212100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 440000814 (or 440000807 counting only the distinct ones).
The product of its (nonzero) digits is 32, while the sum is 15.
Adding to 12012021212100 its reverse (121212021021), we get a palindrome (12133233233121).
The spelling of 12012021212100 in words is "twelve trillion, twelve billion, twenty-one million, two hundred twelve thousand, one hundred".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •