Base | Representation |
---|---|
bin | 1010111011010001100110… |
… | …0010101010100100000110 |
3 | 1120112110211010110202210200 |
4 | 2232310121202222210012 |
5 | 3033312022210411200 |
6 | 41314523110031330 |
7 | 2346641353343205 |
oct | 256643142524406 |
9 | 46473733422720 |
10 | 12013452044550 |
11 | 3911970541aa0 |
12 | 1420354948546 |
13 | 691b2c625a68 |
14 | 2d76503b923c |
15 | 15c76ddb6800 |
hex | aed198aa906 |
12013452044550 has 144 divisors (see below), whose sum is σ = 35959492588032. Its totient is φ = 2850387019200.
The previous prime is 12013452044527. The next prime is 12013452044563. The reversal of 12013452044550 is 5544025431021.
12013452044550 is a `hidden beast` number, since 1 + 2 + 0 + 1 + 3 + 45 + 20 + 44 + 550 = 666.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 25586074 + ... + 26051373.
It is an arithmetic number, because the mean of its divisors is an integer number (249718698528).
Almost surely, 212013452044550 is an apocalyptic number.
12013452044550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12013452044550 is an abundant number, since it is smaller than the sum of its proper divisors (23946040543482).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12013452044550 is a wasteful number, since it uses less digits than its factorization.
12013452044550 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51637523 (or 51637515 counting only the distinct ones).
The product of its (nonzero) digits is 96000, while the sum is 36.
Adding to 12013452044550 its reverse (5544025431021), we get a palindrome (17557477475571).
The spelling of 12013452044550 in words is "twelve trillion, thirteen billion, four hundred fifty-two million, forty-four thousand, five hundred fifty".
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