Base | Representation |
---|---|
bin | 10110100010101011… |
… | …11011001010111000 |
3 | 1011020102021101211010 |
4 | 23101111323022320 |
5 | 144241120320440 |
6 | 5320514233520 |
7 | 605621216016 |
oct | 132125731270 |
9 | 34212241733 |
10 | 12102120120 |
11 | 5150370a72 |
12 | 2418b858a0 |
13 | 11ab36b32c |
14 | 82b4018b6 |
15 | 4ac6e3580 |
hex | 2d157b2b8 |
12102120120 has 64 divisors (see below), whose sum is σ = 36921744000. Its totient is φ = 3172531328.
The previous prime is 12102120113. The next prime is 12102120127. The reversal of 12102120120 is 2102120121.
It is an interprime number because it is at equal distance from previous prime (12102120113) and next prime (12102120127).
It is a super-2 number, since 2×121021201202 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (12).
It is a junction number, because it is equal to n+sod(n) for n = 12102120096 and 12102120105.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12102120127) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 847590 + ... + 861749.
It is an arithmetic number, because the mean of its divisors is an integer number (576902250).
Almost surely, 212102120120 is an apocalyptic number.
12102120120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
12102120120 is an abundant number, since it is smaller than the sum of its proper divisors (24819623880).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12102120120 is a wasteful number, since it uses less digits than its factorization.
12102120120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1709412 (or 1709408 counting only the distinct ones).
The product of its (nonzero) digits is 16, while the sum is 12.
Adding to 12102120120 its reverse (2102120121), we get a palindrome (14204240241).
Subtracting from 12102120120 its reverse (2102120121), we obtain a palindrome (9999999999).
It can be divided in two parts, 121021 and 20120, that added together give a palindrome (141141).
The spelling of 12102120120 in words is "twelve billion, one hundred two million, one hundred twenty thousand, one hundred twenty".
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