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1225201233400 = 235259711462403
BaseRepresentation
bin10001110101000011101…
…011110010110111111000
311100010110101021102010021
4101311003223302313320
5130033203003432100
62334503310300224
7154342425436504
oct21650353626770
94303411242107
101225201233400
11432672178811
121795514b7674
138b6c771aa31
144342b4d5304
1521d0c3aca1a
hex11d43af2df8

1225201233400 has 96 divisors (see below), whose sum is σ = 2937677155200. Its totient is φ = 474988169600.

The previous prime is 1225201233353. The next prime is 1225201233409. The reversal of 1225201233400 is 43321025221.

It is a super-2 number, since 2×12252012334002 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (25).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1225201233409) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 106599 + ... + 1569001.

It is an arithmetic number, because the mean of its divisors is an integer number (30600803700).

Almost surely, 21225201233400 is an apocalyptic number.

1225201233400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1225201233400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1468838577600).

1225201233400 is an abundant number, since it is smaller than the sum of its proper divisors (1712475921800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1225201233400 is a wasteful number, since it uses less digits than its factorization.

1225201233400 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1462549 (or 1462540 counting only the distinct ones).

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 1225201233400 its reverse (43321025221), we get a palindrome (1268522258621).

The spelling of 1225201233400 in words is "one trillion, two hundred twenty-five billion, two hundred one million, two hundred thirty-three thousand, four hundred".

Divisors: 1 2 4 5 8 10 20 25 40 50 59 71 100 118 142 200 236 284 295 355 472 568 590 710 1180 1420 1475 1775 2360 2840 2950 3550 4189 5900 7100 8378 11800 14200 16756 20945 33512 41890 83780 104725 167560 209450 418900 837800 1462403 2924806 5849612 7312015 11699224 14624030 29248060 36560075 58496120 73120150 86281777 103830613 146240300 172563554 207661226 292480600 345127108 415322452 431408885 519153065 690254216 830644904 862817770 1038306130 1725635540 2076612260 2157044425 2595765325 3451271080 4153224520 4314088850 5191530650 6126006167 8628177700 10383061300 12252012334 17256355400 20766122600 24504024668 30630030835 49008049336 61260061670 122520123340 153150154175 245040246680 306300308350 612600616700 1225201233400