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123031403100150 = 235216312973879691
BaseRepresentation
bin11011111110010101111011…
…000100111111011111110110
3121010121200120000112002022220
4123332111323010333133312
5112111221303143201100
61113355502445503210
734625503601324136
oct3376257304773766
9533550500462286
10123031403100150
113622436369a916
1211970387b71b06
135385a71c1752c
142254a7488cac6
15e354e0c7baa0
hex6fe57b13f7f6

123031403100150 has 96 divisors (see below), whose sum is σ = 307226539897728. Its totient is φ = 32581946995200.

The previous prime is 123031403100113. The next prime is 123031403100167. The reversal of 123031403100150 is 51001304130321.

It is a super-2 number, since 2×1230314031001502 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 123031403100150.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 29771805 + ... + 33651495.

It is an arithmetic number, because the mean of its divisors is an integer number (3200276457268).

Almost surely, 2123031403100150 is an apocalyptic number.

123031403100150 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 123031403100150, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (153613269948864).

123031403100150 is an abundant number, since it is smaller than the sum of its proper divisors (184195136797578).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

123031403100150 is a wasteful number, since it uses less digits than its factorization.

123031403100150 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3881166 (or 3881161 counting only the distinct ones).

The product of its (nonzero) digits is 1080, while the sum is 24.

Adding to 123031403100150 its reverse (51001304130321), we get a palindrome (174032707230471).

The spelling of 123031403100150 in words is "one hundred twenty-three trillion, thirty-one billion, four hundred three million, one hundred thousand, one hundred fifty".

Divisors: 1 2 3 5 6 10 15 25 30 50 75 150 163 326 489 815 978 1297 1630 2445 2594 3891 4075 4890 6485 7782 8150 12225 12970 19455 24450 32425 38910 64850 97275 194550 211411 422822 634233 1057055 1268466 2114110 3171165 3879691 5285275 6342330 7759382 10570550 11639073 15855825 19398455 23278146 31711650 38796910 58195365 96992275 116390730 193984550 290976825 581953650 632389633 1264779266 1897168899 3161948165 3794337798 5031959227 6323896330 9485844495 10063918454 15095877681 15809740825 18971688990 25159796135 30191755362 31619481650 47429222475 50319592270 75479388405 94858444950 125798980675 150958776810 251597961350 377396942025 754793884050 820209354001 1640418708002 2460628062003 4101046770005 4921256124006 8202093540010 12303140310015 20505233850025 24606280620030 41010467700050 61515701550075 123031403100150