Base | Representation |
---|---|
bin | 11100011111101001100101… |
… | …000100010110000100110100 |
3 | 121102201111110210101221000010 |
4 | 130133221211010112010310 |
5 | 112411221333324304000 |
6 | 1122311155000220220 |
7 | 35253042441012642 |
oct | 3437514504260464 |
9 | 542644423357003 |
10 | 125320251400500 |
11 | 36a270249069a2 |
12 | 1207baa276a670 |
13 | 54c0858b0a450 |
14 | 22d37653a2192 |
15 | e74d023b0d50 |
hex | 71fa65116134 |
125320251400500 has 96 divisors (see below), whose sum is σ = 393004308453120. Its totient is φ = 30848061878400.
The previous prime is 125320251400489. The next prime is 125320251400573. The reversal of 125320251400500 is 5004152023521.
It is a super-2 number, since 2×1253202514005002 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3213320280 + ... + 3213359279.
It is an arithmetic number, because the mean of its divisors is an integer number (4093794879720).
Almost surely, 2125320251400500 is an apocalyptic number.
125320251400500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
125320251400500 is an abundant number, since it is smaller than the sum of its proper divisors (267684057052620).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
125320251400500 is a wasteful number, since it uses less digits than its factorization.
125320251400500 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6426679594 (or 6426679582 counting only the distinct ones).
The product of its (nonzero) digits is 12000, while the sum is 30.
The spelling of 125320251400500 in words is "one hundred twenty-five trillion, three hundred twenty billion, two hundred fifty-one million, four hundred thousand, five hundred".
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