1300013440 has 128 divisors (see below), whose sum is σ = 3569184000. Its totient is φ = 447805440.

The previous prime is 1300013431. The next prime is 1300013503. The reversal of 1300013440 is 443100031.

It is a tau number, because it is divible by the number of its divisors (128).

It is a Harshad number since it is a multiple of its sum of digits (16).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 128901 + ... + 138619.

It is an arithmetic number, because the mean of its divisors is an integer number (27884250).

Almost surely, 2^1300013440 is an apocalyptic number.

1300013440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1300013440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1784592000).

1300013440 is an abundant number, since it is smaller than the sum of its proper divisors (2269170560).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1300013440 is a wasteful number, since it uses less digits than its factorization.

1300013440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9768 (or 9756 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 16.

The square root of 1300013440 is about 36055.6991334241. The cubic root of 1300013440 is about 1091.3966441559.

Adding to 1300013440 its reverse (443100031), we get a palindrome (1743113471).

The spelling of 1300013440 in words is "one billion, three hundred million, thirteen thousand, four hundred forty".