Base | Representation |
---|---|
bin | 11000001101111110… |
… | …01101000010010010 |
3 | 1020120010210211021120 |
4 | 30012333031002102 |
5 | 203112021234100 |
6 | 5550104503110 |
7 | 640130212122 |
oct | 140677150222 |
9 | 36503724246 |
10 | 13002133650 |
11 | 5572402500 |
12 | 262a47aa96 |
13 | 12c296ac0c |
14 | 8b4b62c82 |
15 | 5117240a0 |
hex | 306fcd092 |
13002133650 has 144 divisors (see below), whose sum is σ = 35533663200. Its totient is φ = 3143993600.
The previous prime is 13002133649. The next prime is 13002133667. The reversal of 13002133650 is 5633120031.
It is a happy number.
It is a self number, because there is not a number n which added to its sum of digits gives 13002133650.
It is an unprimeable number.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 10326721 + ... + 10327979.
It is an arithmetic number, because the mean of its divisors is an integer number (246761550).
Almost surely, 213002133650 is an apocalyptic number.
13002133650 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 13002133650, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17766831600).
13002133650 is an abundant number, since it is smaller than the sum of its proper divisors (22531529550).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13002133650 is a wasteful number, since it uses less digits than its factorization.
13002133650 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1865 (or 1849 counting only the distinct ones).
The product of its (nonzero) digits is 1620, while the sum is 24.
Adding to 13002133650 its reverse (5633120031), we get a palindrome (18635253681).
The spelling of 13002133650 in words is "thirteen billion, two million, one hundred thirty-three thousand, six hundred fifty".
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