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130044155040 = 25325157575213
BaseRepresentation
bin111100100011100111…
…1000101010010100000
3110102200000000112221200
41321013033011102200
54112312300430130
6135424053321200
712252421036152
oct1710717052240
9412600015850
10130044155040
11501735984a8
1221253636200
13c356094687
1464192c0ad2
1535b1b86760
hex1e473c54a0

130044155040 has 144 divisors (see below), whose sum is σ = 446603052168. Its totient is φ = 34457499648.

The previous prime is 130044155027. The next prime is 130044155057. The reversal of 130044155040 is 40551440031.

It is a happy number.

130044155040 is a `hidden beast` number, since 1 + 30 + 0 + 4 + 41 + 550 + 40 = 666.

It can be written as a sum of positive squares in 4 ways, for example, as 111601428624 + 18442726416 = 334068^2 + 135804^2 .

It is a tau number, because it is divible by the number of its divisors (144).

It is a super-2 number, since 2×1300441550402 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130044154995 and 130044155013.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 61527 + ... + 513686.

Almost surely, 2130044155040 is an apocalyptic number.

130044155040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130044155040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (223301526084).

130044155040 is an abundant number, since it is smaller than the sum of its proper divisors (316558897128).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130044155040 is a wasteful number, since it uses less digits than its factorization.

130044155040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 575391 (or 575380 counting only the distinct ones).

The product of its (nonzero) digits is 4800, while the sum is 27.

Adding to 130044155040 its reverse (40551440031), we get a palindrome (170595595071).

It can be divided in two parts, 1300441 and 55040, that added together give a triangular number (1355481 = T1646).

The spelling of 130044155040 in words is "one hundred thirty billion, forty-four million, one hundred fifty-five thousand, forty".

Divisors: 1 2 3 4 5 6 8 9 10 12 15 16 18 20 24 30 32 36 40 45 48 60 72 80 90 96 120 144 157 160 180 240 288 314 360 471 480 628 720 785 942 1256 1413 1440 1570 1884 2355 2512 2826 3140 3768 4710 5024 5652 6280 7065 7536 9420 11304 12560 14130 15072 18840 22608 25120 28260 37680 45216 56520 75360 113040 226080 575213 1150426 1725639 2300852 2876065 3451278 4601704 5176917 5752130 6902556 8628195 9203408 10353834 11504260 13805112 17256390 18406816 20707668 23008520 25884585 27610224 34512780 41415336 46017040 51769170 55220448 69025560 82830672 90308441 92034080 103538340 138051120 165661344 180616882 207076680 270925323 276102240 361233764 414153360 451542205 541850646 722467528 812775969 828306720 903084410 1083701292 1354626615 1444935056 1625551938 1806168820 2167402584 2709253230 2889870112 3251103876 3612337640 4063879845 4334805168 5418506460 6502207752 7224675280 8127759690 8669610336 10837012920 13004415504 14449350560 16255519380 21674025840 26008831008 32511038760 43348051680 65022077520 130044155040