Base | Representation |
---|---|
bin | 111100100101010111… |
… | …1100110111110110100 |
3 | 110102211002202212022020 |
4 | 1321022233212332310 |
5 | 4112422332411200 |
6 | 135433555033140 |
7 | 12254034236451 |
oct | 1711257467664 |
9 | 412732685266 |
10 | 130103013300 |
11 | 501a3839597 |
12 | 2126b29b7b0 |
13 | c365331a50 |
14 | 6423042828 |
15 | 35b6e10ea0 |
hex | 1e4abe6fb4 |
130103013300 has 144 divisors (see below), whose sum is σ = 408976532160. Its totient is φ = 31741839360.
The previous prime is 130103013289. The next prime is 130103013301. The reversal of 130103013300 is 3310301031.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 130103013300.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130103013301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 293091 + ... + 588309.
Almost surely, 2130103013300 is an apocalyptic number.
130103013300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 130103013300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (204488266080).
130103013300 is an abundant number, since it is smaller than the sum of its proper divisors (278873518860).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130103013300 is a wasteful number, since it uses less digits than its factorization.
130103013300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 295362 (or 295355 counting only the distinct ones).
The product of its (nonzero) digits is 81, while the sum is 15.
Adding to 130103013300 its reverse (3310301031), we get a palindrome (133413314331).
The spelling of 130103013300 in words is "one hundred thirty billion, one hundred three million, thirteen thousand, three hundred".
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