130314120333440 has 128 divisors (see below), whose sum is σ = 316674834577920. Its totient is φ = 51271773880320.

The previous prime is 130314120333437. The next prime is 130314120333443. The reversal of 130314120333440 is 44333021413031.

It is a happy number.

It is an interprime number because it is at equal distance from previous prime (130314120333437) and next prime (130314120333443).

It is a tau number, because it is divible by the number of its divisors (128).

It is a Harshad number since it is a multiple of its sum of digits (32).

It is a junction number, because it is equal to n+sod(n) for n = 130314120333397 and 130314120333406.

It is not an unprimeable number, because it can be changed into a prime (130314120333443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3679985 + ... + 16558095.

It is an arithmetic number, because the mean of its divisors is an integer number (2474022145140).

Almost surely, 2^{130314120333440} is an apocalyptic number.

130314120333440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130314120333440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (158337417288960).

130314120333440 is an abundant number, since it is smaller than the sum of its proper divisors (186360714244480).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130314120333440 is a wasteful number, since it uses less digits than its factorization.

130314120333440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12878390 (or 12878378 counting only the distinct ones).

The product of its (nonzero) digits is 31104, while the sum is 32.

Adding to 130314120333440 its reverse (44333021413031), we get a palindrome (174647141746471).

The spelling of 130314120333440 in words is "one hundred thirty trillion, three hundred fourteen billion, one hundred twenty million, three hundred thirty-three thousand, four hundred forty".