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130402110300 = 223527115645113
BaseRepresentation
bin111100101110010010…
…0100100101101011100
3110110120221120120020220
41321130210210231130
54114030420012200
6135523401441340
712264325435410
oct1713444445534
9413527516226
10130402110300
11503376565a0
12213334a0250
13c3b22a4817
146450a5cd40
1535d32e24a0
hex1e5c924b5c

130402110300 has 144 divisors (see below), whose sum is σ = 470396059392. Its totient is φ = 27096537600.

The previous prime is 130402110299. The next prime is 130402110301. The reversal of 130402110300 is 3011204031.

130402110300 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (130402110299) and next prime (130402110301).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 130402110300.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130402110301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 2799457 + ... + 2845656.

Almost surely, 2130402110300 is an apocalyptic number.

130402110300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

130402110300 is an abundant number, since it is smaller than the sum of its proper divisors (339993949092).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130402110300 is a wasteful number, since it uses less digits than its factorization.

130402110300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5645148 (or 5645141 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 130402110300 its reverse (3011204031), we get a palindrome (133413314331).

The spelling of 130402110300 in words is "one hundred thirty billion, four hundred two million, one hundred ten thousand, three hundred".

Divisors: 1 2 3 4 5 6 7 10 11 12 14 15 20 21 22 25 28 30 33 35 42 44 50 55 60 66 70 75 77 84 100 105 110 132 140 150 154 165 175 210 220 231 275 300 308 330 350 385 420 462 525 550 660 700 770 825 924 1050 1100 1155 1540 1650 1925 2100 2310 3300 3850 4620 5775 7700 11550 23100 5645113 11290226 16935339 22580452 28225565 33870678 39515791 56451130 62096243 67741356 79031582 84676695 112902260 118547373 124192486 141127825 158063164 169353390 186288729 197578955 237094746 248384972 282255650 310481215 338706780 372577458 395157910 423383475 434673701 474189492 564511300 592736865 620962430 745154916 790315820 846766950 869347402 931443645 987894775 1185473730 1241924860 1304021103 1552406075 1693533900 1738694804 1862887290 1975789550 2173368505 2370947460 2608042206 2963684325 3104812150 3725774580 3951579100 4346737010 4657218225 5216084412 5927368650 6209624300 6520105515 8693474020 9314436450 10866842525 11854737300 13040211030 18628872900 21733685050 26080422060 32600527575 43467370100 65201055150 130402110300