Base | Representation |
---|---|
bin | 10011000000011010010… |
… | …110000000001000011110 |
3 | 11121212022012012220201020 |
4 | 103000122112000020132 |
5 | 132344404140031220 |
6 | 2440004121425010 |
7 | 163235450050440 |
oct | 23003226001036 |
9 | 4555265186636 |
10 | 1306112033310 |
11 | 463a12213297 |
12 | 19117233b166 |
13 | 9622045abb6 |
14 | 473051dc490 |
15 | 23e957dd040 |
hex | 1301a58021e |
1306112033310 has 512 divisors, whose sum is σ = 3837586636800. Its totient is φ = 278359910400.
The previous prime is 1306112033309. The next prime is 1306112033311. The reversal of 1306112033310 is 133302116031.
It is an interprime number because it is at equal distance from previous prime (1306112033309) and next prime (1306112033311).
It is a super-2 number, since 2×13061120333102 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1306112033311) by changing a digit.
It is a polite number, since it can be written in 255 ways as a sum of consecutive naturals, for example, 3117212281 + ... + 3117212699.
It is an arithmetic number, because the mean of its divisors is an integer number (7495286400).
Almost surely, 21306112033310 is an apocalyptic number.
1306112033310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 1306112033310, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1918793318400).
1306112033310 is an abundant number, since it is smaller than the sum of its proper divisors (2531474603490).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1306112033310 is a wasteful number, since it uses less digits than its factorization.
1306112033310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 696.
The product of its (nonzero) digits is 972, while the sum is 24.
Adding to 1306112033310 its reverse (133302116031), we get a palindrome (1439414149341).
The spelling of 1306112033310 in words is "one trillion, three hundred six billion, one hundred twelve million, thirty-three thousand, three hundred ten".
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