Base | Representation |
---|---|
bin | 11101110010010101011010… |
… | …110000011001000101100000 |
3 | 122011211200212221011112211102 |
4 | 131302111122300121011200 |
5 | 114132320222423133100 |
6 | 1142341345100533532 |
7 | 36410414421223205 |
oct | 3562253260310540 |
9 | 564750787145742 |
10 | 131002320130400 |
11 | 38817854543464 |
12 | 12839163b512a8 |
13 | 5813609423744 |
14 | 244c7907d3cac |
15 | 1022a0e85acd5 |
hex | 77255ac19160 |
131002320130400 has 144 divisors (see below), whose sum is σ = 338857100507520. Its totient is φ = 49284240384000.
The previous prime is 131002320130393. The next prime is 131002320130411. The reversal of 131002320130400 is 4031023200131.
It is a super-3 number, since 3×1310023201304003 (a number of 43 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 16223450 + ... + 22917350.
It is an arithmetic number, because the mean of its divisors is an integer number (2353174309080).
Almost surely, 2131002320130400 is an apocalyptic number.
131002320130400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131002320130400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (169428550253760).
131002320130400 is an abundant number, since it is smaller than the sum of its proper divisors (207854780377120).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131002320130400 is a wasteful number, since it uses less digits than its factorization.
131002320130400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6695377 (or 6695364 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 131002320130400 its reverse (4031023200131), we get a palindrome (135033343330531).
The spelling of 131002320130400 in words is "one hundred thirty-one trillion, two billion, three hundred twenty million, one hundred thirty thousand, four hundred".
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