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131002320130400 = 25521714396693901
BaseRepresentation
bin11101110010010101011010…
…110000011001000101100000
3122011211200212221011112211102
4131302111122300121011200
5114132320222423133100
61142341345100533532
736410414421223205
oct3562253260310540
9564750787145742
10131002320130400
1138817854543464
1212839163b512a8
135813609423744
14244c7907d3cac
151022a0e85acd5
hex77255ac19160

131002320130400 has 144 divisors (see below), whose sum is σ = 338857100507520. Its totient is φ = 49284240384000.

The previous prime is 131002320130393. The next prime is 131002320130411. The reversal of 131002320130400 is 4031023200131.

It is a super-3 number, since 3×1310023201304003 (a number of 43 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 16223450 + ... + 22917350.

It is an arithmetic number, because the mean of its divisors is an integer number (2353174309080).

Almost surely, 2131002320130400 is an apocalyptic number.

131002320130400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131002320130400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (169428550253760).

131002320130400 is an abundant number, since it is smaller than the sum of its proper divisors (207854780377120).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131002320130400 is a wasteful number, since it uses less digits than its factorization.

131002320130400 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6695377 (or 6695364 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 131002320130400 its reverse (4031023200131), we get a palindrome (135033343330531).

The spelling of 131002320130400 in words is "one hundred thirty-one trillion, two billion, three hundred twenty million, one hundred thirty thousand, four hundred".

Divisors: 1 2 4 5 8 10 16 17 20 25 32 34 40 50 68 80 85 100 136 160 170 200 272 340 400 425 544 680 800 850 1360 1439 1700 2720 2878 3400 5756 6800 7195 11512 13600 14390 23024 24463 28780 35975 46048 48926 57560 71950 97852 115120 122315 143900 195704 230240 244630 287800 391408 489260 575600 611575 782816 978520 1151200 1223150 1957040 2446300 3914080 4892600 6693901 9785200 13387802 19570400 26775604 33469505 53551208 66939010 107102416 113796317 133878020 167347525 214204832 227592634 267756040 334695050 455185268 535512080 568981585 669390100 910370536 1071024160 1137963170 1338780200 1820741072 2275926340 2677560400 2844907925 3641482144 4551852680 5355120800 5689815850 9103705360 9632523539 11379631700 18207410720 19265047078 22759263400 38530094156 45518526800 48162617695 77060188312 91037053600 96325235390 154120376624 163752900163 192650470780 240813088475 308240753248 327505800326 385300941560 481626176950 655011600652 770601883120 818764500815 963252353900 1310023201304 1541203766240 1637529001630 1926504707800 2620046402608 3275058003260 3853009415600 4093822504075 5240092805216 6550116006520 7706018831200 8187645008150 13100232013040 16375290016300 26200464026080 32750580032600 65501160065200 131002320130400