Base | Representation |
---|---|
bin | 111101000000011011… |
… | …1010110001000110000 |
3 | 110112011101022221011010 |
4 | 1322000313112020300 |
5 | 4121302304323440 |
6 | 140104032350520 |
7 | 12315401135433 |
oct | 1720067261060 |
9 | 415141287133 |
10 | 131011011120 |
11 | 5061a333810 |
12 | 214833a5440 |
13 | c47b498872 |
14 | 64ab88181a |
15 | 361b9bc580 |
hex | 1e80dd6230 |
131011011120 has 80 divisors (see below), whose sum is σ = 443055428352. Its totient is φ = 31760244480.
The previous prime is 131011011017. The next prime is 131011011133. The reversal of 131011011120 is 21110110131.
It is a tau number, because it is divible by the number of its divisors (80).
It is a Harshad number since it is a multiple of its sum of digits (12).
It is a junction number, because it is equal to n+sod(n) for n = 131011011096 and 131011011105.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 24810052 + ... + 24815331.
Almost surely, 2131011011120 is an apocalyptic number.
131011011120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131011011120 is an abundant number, since it is smaller than the sum of its proper divisors (312044417232).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131011011120 is a wasteful number, since it uses less digits than its factorization.
131011011120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 49625410 (or 49625404 counting only the distinct ones).
The product of its (nonzero) digits is 6, while the sum is 12.
Adding to 131011011120 its reverse (21110110131), we get a palindrome (152121121251).
It can be divided in two parts, 1310110111 and 20, that added together give a palindrome (1310110131).
The spelling of 131011011120 in words is "one hundred thirty-one billion, eleven million, eleven thousand, one hundred twenty".
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