Base | Representation |
---|---|
bin | 11101110010011101100111… |
… | …110111011011000111101110 |
3 | 122011212112121220111220121210 |
4 | 131302131213313123013232 |
5 | 114132441243240342032 |
6 | 1142345403211135250 |
7 | 36411145635044502 |
oct | 3562354767330756 |
9 | 564775556456553 |
10 | 131011130012142 |
11 | 38820565490a66 |
12 | 1283aa02444526 |
13 | 58143b1699513 |
14 | 244cd8887a302 |
15 | 1022d77ed12cc |
hex | 772767ddb1ee |
131011130012142 has 32 divisors (see below), whose sum is σ = 280334428341120. Its totient is φ = 40693707335520.
The previous prime is 131011130012137. The next prime is 131011130012179. The reversal of 131011130012142 is 241210031110131.
It is a happy number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9419832708 + ... + 9419846615.
It is an arithmetic number, because the mean of its divisors is an integer number (8760450885660).
Almost surely, 2131011130012142 is an apocalyptic number.
131011130012142 is an abundant number, since it is smaller than the sum of its proper divisors (149323298328978).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131011130012142 is a wasteful number, since it uses less digits than its factorization.
131011130012142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18839679408.
The product of its (nonzero) digits is 144, while the sum is 21.
Adding to 131011130012142 its reverse (241210031110131), we get a palindrome (372221161122273).
The spelling of 131011130012142 in words is "one hundred thirty-one trillion, eleven billion, one hundred thirty million, twelve thousand, one hundred forty-two".
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