Base | Representation |
---|---|
bin | 1011111010110001011100… |
… | …0111010101110011110000 |
3 | 1201101202120111111010002020 |
4 | 2332230113013111303300 |
5 | 3204200133223123100 |
6 | 43512014131151440 |
7 | 2521520405551416 |
oct | 276542707256360 |
9 | 51352514433066 |
10 | 13104333020400 |
11 | 41a25753a7196 |
12 | 157785a745580 |
13 | 74096c0a904b |
14 | 3343787272b6 |
15 | 17ad18ec95a0 |
hex | beb171d5cf0 |
13104333020400 has 120 divisors (see below), whose sum is σ = 42132446517504. Its totient is φ = 3481593926400.
The previous prime is 13104333020357. The next prime is 13104333020473. The reversal of 13104333020400 is 402033340131.
It is a tau number, because it is divible by the number of its divisors (120).
It is a Harshad number since it is a multiple of its sum of digits (24).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 19822914 + ... + 20473313.
Almost surely, 213104333020400 is an apocalyptic number.
13104333020400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13104333020400 is an abundant number, since it is smaller than the sum of its proper divisors (29028113497104).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13104333020400 is a wasteful number, since it uses less digits than its factorization.
13104333020400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 40296519 (or 40296508 counting only the distinct ones).
The product of its (nonzero) digits is 2592, while the sum is 24.
Adding to 13104333020400 its reverse (402033340131), we get a palindrome (13506366360531).
The spelling of 13104333020400 in words is "thirteen trillion, one hundred four billion, three hundred thirty-three million, twenty thousand, four hundred".
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