13104411325500 has 96 divisors (see below), whose sum is σ = 41629140903168. Its totient is φ = 3176826984000.

The previous prime is 13104411325477. The next prime is 13104411325567. The reversal of 13104411325500 is 552311440131.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 397086874 + ... + 397119873.

It is an arithmetic number, because the mean of its divisors is an integer number (433636884408).

Almost surely, 2^{13104411325500} is an apocalyptic number.

13104411325500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13104411325500 is an abundant number, since it is smaller than the sum of its proper divisors (28524729577668).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13104411325500 is a wasteful number, since it uses less digits than its factorization.

13104411325500 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 794206780 (or 794206768 counting only the distinct ones).

The product of its (nonzero) digits is 7200, while the sum is 30.

Adding to 13104411325500 its reverse (552311440131), we get a palindrome (13656722765631).

The spelling of 13104411325500 in words is "thirteen trillion, one hundred four billion, four hundred eleven million, three hundred twenty-five thousand, five hundred".