1311040202100 has 144 divisors (see below), whose sum is σ = 4021650931200. Its totient is φ = 328827150720.

The previous prime is 1311040202093. The next prime is 1311040202159. The reversal of 1311040202100 is 12020401131.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 1311040202100.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 35064 + ... + 1619663.

Almost surely, 2^{1311040202100} is an apocalyptic number.

1311040202100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1311040202100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2010825465600).

1311040202100 is an abundant number, since it is smaller than the sum of its proper divisors (2710610729100).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1311040202100 is a wasteful number, since it uses less digits than its factorization.

1311040202100 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1654902 (or 1654895 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 1311040202100 its reverse (12020401131), we get a palindrome (1323060603231).

The spelling of 1311040202100 in words is "one trillion, three hundred eleven billion, forty million, two hundred two thousand, one hundred".