13113433140 has 96 divisors (see below), whose sum is σ = 38905816320. Its totient is φ = 3288815616.

The previous prime is 13113433127. The next prime is 13113433211. The reversal of 13113433140 is 4133431131.

13113433140 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a self number, because there is not a number n which added to its sum of digits gives 13113433140.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1698529 + ... + 1706231.

It is an arithmetic number, because the mean of its divisors is an integer number (405268920).

Almost surely, 2^13113433140 is an apocalyptic number.

13113433140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13113433140, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19452908160).

13113433140 is an abundant number, since it is smaller than the sum of its proper divisors (25792383180).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13113433140 is a wasteful number, since it uses less digits than its factorization.

13113433140 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9401 (or 9399 counting only the distinct ones).

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 13113433140 its reverse (4133431131), we get a palindrome (17246864271).

The spelling of 13113433140 in words is "thirteen billion, one hundred thirteen million, four hundred thirty-three thousand, one hundred forty".