Base | Representation |
---|---|
bin | 11101110100010110101010… |
… | …110111011101001110101010 |
3 | 122012022222002221211112201220 |
4 | 131310112222313131032222 |
5 | 114142103434344110010 |
6 | 1142525220245522510 |
7 | 36423426534140205 |
oct | 3564265267351652 |
9 | 565288087745656 |
10 | 131141103113130 |
11 | 388706a1958500 |
12 | 12860036113436 |
13 | 5823725b13676 |
14 | 245539854293c |
15 | 10264337ce970 |
hex | 7745aaddd3aa |
131141103113130 has 96 divisors (see below), whose sum is σ = 346645693800000. Its totient is φ = 31728071147520.
The previous prime is 131141103113099. The next prime is 131141103113147. The reversal of 131141103113130 is 31311301141131.
It is a self number, because there is not a number n which added to its sum of digits gives 131141103113130.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 34388055 + ... + 38010794.
It is an arithmetic number, because the mean of its divisors is an integer number (3610892643750).
Almost surely, 2131141103113130 is an apocalyptic number.
131141103113130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131141103113130 is an abundant number, since it is smaller than the sum of its proper divisors (215504590686870).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131141103113130 is a wasteful number, since it uses less digits than its factorization.
131141103113130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 72399380 (or 72399369 counting only the distinct ones).
The product of its (nonzero) digits is 324, while the sum is 24.
Adding to 131141103113130 its reverse (31311301141131), we get a palindrome (162452404254261).
The spelling of 131141103113130 in words is "one hundred thirty-one trillion, one hundred forty-one billion, one hundred three million, one hundred thirteen thousand, one hundred thirty".
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