Base | Representation |
---|---|
bin | 11101110101100011111110… |
… | …001000010111011100100000 |
3 | 122012121220100110110111012100 |
4 | 131311203332020113130200 |
5 | 114144433431213332230 |
6 | 1143031304340130400 |
7 | 36432425431543614 |
oct | 3565437610273440 |
9 | 565556313414170 |
10 | 131224104433440 |
11 | 388a2914a46997 |
12 | 1287413b096a00 |
13 | 582b4c29a2955 |
14 | 24593cdb49344 |
15 | 1028690503660 |
hex | 7758fe217720 |
131224104433440 has 144 divisors (see below), whose sum is σ = 459905020251768. Its totient is φ = 34047335190528.
The previous prime is 131224104433427. The next prime is 131224104433489. The reversal of 131224104433440 is 44334401422131.
131224104433440 is a `hidden beast` number, since 1 + 3 + 1 + 2 + 241 + 0 + 44 + 334 + 40 = 666.
It can be written as a sum of positive squares in 4 ways, for example, as 128835484727184 + 2388619706256 = 11350572^2 + 1545516^2 .
It is a tau number, because it is divible by the number of its divisors (144).
It is a Harshad number since it is a multiple of its sum of digits (36).
It is a junction number, because it is equal to n+sod(n) for n = 131224104433395 and 131224104433404.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1231404157 + ... + 1231510716.
Almost surely, 2131224104433440 is an apocalyptic number.
131224104433440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131224104433440 is an abundant number, since it is smaller than the sum of its proper divisors (328680915818328).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131224104433440 is a wasteful number, since it uses less digits than its factorization.
131224104433440 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2462914931 (or 2462914920 counting only the distinct ones).
The product of its (nonzero) digits is 110592, while the sum is 36.
Adding to 131224104433440 its reverse (44334401422131), we get a palindrome (175558505855571).
The spelling of 131224104433440 in words is "one hundred thirty-one trillion, two hundred twenty-four billion, one hundred four million, four hundred thirty-three thousand, four hundred forty".
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