Base | Representation |
---|---|
bin | 11101110110110100111111… |
… | …101010011001100111000000 |
3 | 122012221012220120000202200021 |
4 | 131312310333222121213000 |
5 | 114202400114411021120 |
6 | 1143135253230103224 |
7 | 36441625356202333 |
oct | 3566647752314700 |
9 | 565835816022607 |
10 | 131311103220160 |
11 | 389267a9549026 |
12 | 12888b7a94ab14 |
13 | 5836778aa7386 |
14 | 245d6c420661a |
15 | 102aa8314baaa |
hex | 776d3fa999c0 |
131311103220160 has 112 divisors (see below), whose sum is σ = 331494709282560. Its totient is φ = 49456317726720.
The previous prime is 131311103220119. The next prime is 131311103220161. The reversal of 131311103220160 is 61022301113131.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131311103220161) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 178511425 + ... + 179245504.
Almost surely, 2131311103220160 is an apocalyptic number.
131311103220160 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131311103220160 is an abundant number, since it is smaller than the sum of its proper divisors (200183606062400).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131311103220160 is a wasteful number, since it uses less digits than its factorization.
131311103220160 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 357757014 (or 357757004 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 25.
Adding to 131311103220160 its reverse (61022301113131), we get a palindrome (192333404333291).
The spelling of 131311103220160 in words is "one hundred thirty-one trillion, three hundred eleven billion, one hundred three million, two hundred twenty thousand, one hundred sixty".
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