131311122000 has 80 divisors (see below), whose sum is σ = 423347076672. Its totient is φ = 35016297600.

The previous prime is 131311121911. The next prime is 131311122001. The reversal of 131311122000 is 221113131.

It is a happy number.

It is a tau number, because it is divible by the number of its divisors (80).

It is a super-2 number, since 2×131311122000² (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131311122001) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10936594 + ... + 10948593.

Almost surely, 2^131311122000 is an apocalyptic number.

131311122000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131311122000 is an abundant number, since it is smaller than the sum of its proper divisors (292035954672).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131311122000 is a wasteful number, since it uses less digits than its factorization.

131311122000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21885213 (or 21885197 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 131311122000 its reverse (221113131), we get a palindrome (131532235131).

The spelling of 131311122000 in words is "one hundred thirty-one billion, three hundred eleven million, one hundred twenty-two thousand".