1313321341440 has 160 divisors (see below), whose sum is σ = 4300928222976. Its totient is φ = 341677015040.

The previous prime is 1313321341439. The next prime is 1313321341441. The reversal of 1313321341440 is 441431233131.

It is an interprime number because it is at equal distance from previous prime (1313321341439) and next prime (1313321341441).

It is a tau number, because it is divible by the number of its divisors (160).

It is a super-2 number, since 2×1313321341440² (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a junction number, because it is equal to n+sod(n) for n = 1313321341398 and 1313321341407.

It is not an unprimeable number, because it can be changed into a prime (1313321341441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1770552 + ... + 2400311.

Almost surely, 2^{1313321341440} is an apocalyptic number.

1313321341440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1313321341440 is an abundant number, since it is smaller than the sum of its proper divisors (2987606881536).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1313321341440 is an equidigital number, since it uses as much as digits as its factorization.

1313321341440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4170930 (or 4170914 counting only the distinct ones).

The product of its (nonzero) digits is 10368, while the sum is 30.

Adding to 1313321341440 its reverse (441431233131), we get a palindrome (1754752574571).

The spelling of 1313321341440 in words is "one trillion, three hundred thirteen billion, three hundred twenty-one million, three hundred forty-one thousand, four hundred forty".