Base | Representation |
---|---|
bin | 11110001111101111101001… |
… | …111000111001110101011100 |
3 | 122102222220112101222001000210 |
4 | 132033233221320321311130 |
5 | 114413423313132221300 |
6 | 1150530030340252420 |
7 | 40006422525624105 |
oct | 3617575170716534 |
9 | 572886471861023 |
10 | 133023356132700 |
11 | 39426985697110 |
12 | 12b049989a1110 |
13 | 592c082b96947 |
14 | 24bc516da93ac |
15 | 105a3994e8050 |
hex | 78fbe9e39d5c |
133023356132700 has 144 divisors (see below), whose sum is σ = 420165158708736. Its totient is φ = 32225423155200.
The previous prime is 133023356132599. The next prime is 133023356132701. The reversal of 133023356132700 is 7231653320331.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133023356132701) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 9467877 + ... + 18859676.
It is an arithmetic number, because the mean of its divisors is an integer number (2917813602144).
Almost surely, 2133023356132700 is an apocalyptic number.
133023356132700 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
133023356132700 is an abundant number, since it is smaller than the sum of its proper divisors (287141802576036).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133023356132700 is a wasteful number, since it uses less digits than its factorization.
133023356132700 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28329004 (or 28328997 counting only the distinct ones).
The product of its (nonzero) digits is 204120, while the sum is 39.
The spelling of 133023356132700 in words is "one hundred thirty-three trillion, twenty-three billion, three hundred fifty-six million, one hundred thirty-two thousand, seven hundred".
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