Base | Representation |
---|---|
bin | 1100000110011010001011… |
… | …0000000111111111001010 |
3 | 1202002212120122201022012220 |
4 | 3001212202300013333022 |
5 | 3220434043011142310 |
6 | 44143515130314510 |
7 | 2542125401103411 |
oct | 301464260077712 |
9 | 52085518638186 |
10 | 13304244240330 |
11 | 426a33103a62a |
12 | 15aa550588a36 |
13 | 75677abb2624 |
14 | 33dd00ad8478 |
15 | 181119763670 |
hex | c19a2c07fca |
13304244240330 has 128 divisors (see below), whose sum is σ = 35509495910400. Its totient is φ = 3176126763264.
The previous prime is 13304244240317. The next prime is 13304244240347. The reversal of 13304244240330 is 3304244240331.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 13304244240291 and 13304244240300.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 7785372 + ... + 9339191.
It is an arithmetic number, because the mean of its divisors is an integer number (277417936800).
Almost surely, 213304244240330 is an apocalyptic number.
13304244240330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13304244240330 is an abundant number, since it is smaller than the sum of its proper divisors (22205251670070).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13304244240330 is a wasteful number, since it uses less digits than its factorization.
13304244240330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17124668.
The product of its (nonzero) digits is 82944, while the sum is 33.
Adding to 13304244240330 its reverse (3304244240331), we get a palindrome (16608488480661).
Subtracting from 13304244240330 its reverse (3304244240331), we obtain a palindrome (9999999999999).
The spelling of 13304244240330 in words is "thirteen trillion, three hundred four billion, two hundred forty-four million, two hundred forty thousand, three hundred thirty".
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