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13311013200 = 2435265316987
BaseRepresentation
bin11000110010110010…
…11111000101010000
31021100200000112100220
430121121133011100
5204230104410300
610040501113040
7650600513442
oct143131370520
937320015326
1013311013200
1157107a1261
1226b59b8780
131341957594
14903ba8492
1552d8d8da0
hex31965f150

13311013200 has 120 divisors (see below), whose sum is σ = 42707424288. Its totient is φ = 3543959040.

The previous prime is 13311013193. The next prime is 13311013207. The reversal of 13311013200 is 231011331.

It is an interprime number because it is at equal distance from previous prime (13311013193) and next prime (13311013207).

It is a tau number, because it is divible by the number of its divisors (120).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 13311013200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13311013207) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 775107 + ... + 792093.

Almost surely, 213311013200 is an apocalyptic number.

13311013200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13311013200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21353712144).

13311013200 is an abundant number, since it is smaller than the sum of its proper divisors (29396411088).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13311013200 is a wasteful number, since it uses less digits than its factorization.

13311013200 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17661 (or 17650 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 13311013200 its reverse (231011331), we get a palindrome (13542024531).

The spelling of 13311013200 in words is "thirteen billion, three hundred eleven million, thirteen thousand, two hundred".

Divisors: 1 2 3 4 5 6 8 10 12 15 16 20 24 25 30 40 48 50 60 75 80 100 120 150 200 240 300 400 600 653 1200 1306 1959 2612 3265 3918 5224 6530 7836 9795 10448 13060 15672 16325 16987 19590 26120 31344 32650 33974 39180 48975 50961 52240 65300 67948 78360 84935 97950 101922 130600 135896 156720 169870 195900 203844 254805 261200 271792 339740 391800 407688 424675 509610 679480 783600 815376 849350 1019220 1274025 1358960 1698700 2038440 2548050 3397400 4076880 5096100 6794800 10192200 11092511 20384400 22185022 33277533 44370044 55462555 66555066 88740088 110925110 133110132 166387665 177480176 221850220 266220264 277312775 332775330 443700440 532440528 554625550 665550660 831938325 887400880 1109251100 1331101320 1663876650 2218502200 2662202640 3327753300 4437004400 6655506600 13311013200