Base | Representation |
---|---|
bin | 1100000111100000000101… |
… | …0110100001000100000000 |
3 | 1202011200000120010021000110 |
4 | 3001320001112201010000 |
5 | 3221241011333411000 |
6 | 44200301252151320 |
7 | 2543361431644011 |
oct | 301700126410400 |
9 | 52150016107013 |
10 | 13323011232000 |
11 | 42772915681a8 |
12 | 15b2109608540 |
13 | 75847bca9722 |
14 | 340ba133b008 |
15 | 181867123850 |
hex | c1e015a1100 |
13323011232000 has 144 divisors (see below), whose sum is σ = 44252382125952. Its totient is φ = 3552802969600.
The previous prime is 13323011231927. The next prime is 13323011232049. The reversal of 13323011232000 is 23211032331.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 69294684 + ... + 69486683.
It is an arithmetic number, because the mean of its divisors is an integer number (307308209208).
Almost surely, 213323011232000 is an apocalyptic number.
13323011232000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13323011232000 is an abundant number, since it is smaller than the sum of its proper divisors (30929370893952).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13323011232000 is an equidigital number, since it uses as much as digits as its factorization.
13323011232000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 138781401 (or 138781377 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 13323011232000 its reverse (23211032331), we get a palindrome (13346222264331).
The spelling of 13323011232000 in words is "thirteen trillion, three hundred twenty-three billion, eleven million, two hundred thirty-two thousand".
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