Base | Representation |
---|---|
bin | 11110010010110001010110… |
… | …111001100011110100111010 |
3 | 122110201210101101210120000120 |
4 | 132102301112321203310322 |
5 | 114430330242410421300 |
6 | 1151205344554314110 |
7 | 40030434614643516 |
oct | 3622612671436472 |
9 | 573653341716016 |
10 | 133231343451450 |
11 | 394a7106054092 |
12 | 12b39163428936 |
13 | 594587ac08b1a |
14 | 24c8607bb3146 |
15 | 10609bdcb03a0 |
hex | 792c56e63d3a |
133231343451450 has 96 divisors (see below), whose sum is σ = 337685770810752. Its totient is φ = 34752854304000.
The previous prime is 133231343451403. The next prime is 133231343451457. The reversal of 133231343451450 is 54154343132331.
It is not an unprimeable number, because it can be changed into a prime (133231343451457) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 38567062 + ... + 41879361.
It is an arithmetic number, because the mean of its divisors is an integer number (3517560112612).
Almost surely, 2133231343451450 is an apocalyptic number.
133231343451450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
133231343451450 is an abundant number, since it is smaller than the sum of its proper divisors (204454427359302).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133231343451450 is a wasteful number, since it uses less digits than its factorization.
133231343451450 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 80446680 (or 80446675 counting only the distinct ones).
The product of its (nonzero) digits is 777600, while the sum is 42.
Adding to 133231343451450 its reverse (54154343132331), we get a palindrome (187385686583781).
The spelling of 133231343451450 in words is "one hundred thirty-three trillion, two hundred thirty-one billion, three hundred forty-three million, four hundred fifty-one thousand, four hundred fifty".
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