| Base | Representation |
|---|---|
| bin | 100111111100100… |
| … | …1110011000110000 |
| 3 | 10110102012102202220 |
| 4 | 1033321032120300 |
| 5 | 10221120314300 |
| 6 | 341001241040 |
| 7 | 45134136135 |
| oct | 11771163060 |
| 9 | 3412172686 |
| 10 | 1340401200 |
| 11 | 628692296 |
| 12 | 314a93180 |
| 13 | 184912308 |
| 14 | ca03a58c |
| 15 | 7ca20da0 |
| hex | 4fe4e630 |
1340401200 has 120 divisors (see below), whose sum is σ = 4310015808. Its totient is φ = 356087040.
The previous prime is 1340401133. The next prime is 1340401201. The reversal of 1340401200 is 21040431.
It is a tau number, because it is divible by the number of its divisors (120).
It is a super-5 number, since 5×13404012005 (a number of 47 digits) contains 55555 as substring. Note that it is a super-d number also for d = 2.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 1340401200.
It is not an unprimeable number, because it can be changed into a prime (1340401201) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 337627 + ... + 341573.
Almost surely, 21340401200 is an apocalyptic number.
1340401200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1340401200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2155007904).
1340401200 is an abundant number, since it is smaller than the sum of its proper divisors (2969614608).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1340401200 is a wasteful number, since it uses less digits than its factorization.
1340401200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4251 (or 4240 counting only the distinct ones).
The product of its (nonzero) digits is 96, while the sum is 15.
The square root of 1340401200 is about 36611.4899997255. The cubic root of 1340401200 is about 1102.5837884500.
Adding to 1340401200 its reverse (21040431), we get a palindrome (1361441631).
The spelling of 1340401200 in words is "one billion, three hundred forty million, four hundred one thousand, two hundred".
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