Base | Representation |
---|---|
bin | 11111110101101111111111… |
… | …111101010001000011101110 |
3 | 200100211000221102012100012220 |
4 | 133311233333331101003232 |
5 | 121323300303412032342 |
6 | 1213454153553340210 |
7 | 41332026040125126 |
oct | 3765577775210356 |
9 | 610730842170186 |
10 | 140033113002222 |
11 | 406897896a7990 |
12 | 13857432267666 |
13 | 601a0b1a03a3b |
14 | 26818d2d55c86 |
15 | 112c8b157b5ec |
hex | 7f5bfff510ee |
140033113002222 has 96 divisors (see below), whose sum is σ = 318468236561280. Its totient is φ = 40697609452800.
The previous prime is 140033113002191. The next prime is 140033113002241. The reversal of 140033113002222 is 222200311330041.
It is a junction number, because it is equal to n+sod(n) for n = 140033113002192 and 140033113002201.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 4150573 + ... + 17242200.
It is an arithmetic number, because the mean of its divisors is an integer number (3317377464180).
Almost surely, 2140033113002222 is an apocalyptic number.
140033113002222 is an abundant number, since it is smaller than the sum of its proper divisors (178435123559058).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
140033113002222 is a wasteful number, since it uses less digits than its factorization.
140033113002222 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21392930 (or 21392889 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 140033113002222 its reverse (222200311330041), we get a palindrome (362233424332263).
The spelling of 140033113002222 in words is "one hundred forty trillion, thirty-three billion, one hundred thirteen million, two thousand, two hundred twenty-two".
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