14025130050 has 96 divisors (see below), whose sum is σ = 38016566784. Its totient is φ = 3406464000.

The previous prime is 14025130043. The next prime is 14025130051. The reversal of 14025130050 is 5003152041.

It is a junction number, because it is equal to n+sod(n) for n = 14025129999 and 14025130026.

It is not an unprimeable number, because it can be changed into a prime (14025130051) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 9661 + ... + 167760.

It is an arithmetic number, because the mean of its divisors is an integer number (396005904).

Almost surely, 2^14025130050 is an apocalyptic number.

14025130050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 14025130050, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19008283392).

14025130050 is an abundant number, since it is smaller than the sum of its proper divisors (23991436734).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14025130050 is a wasteful number, since it uses less digits than its factorization.

14025130050 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 177484 (or 177479 counting only the distinct ones).

The product of its (nonzero) digits is 600, while the sum is 21.

Adding to 14025130050 its reverse (5003152041), we get a palindrome (19028282091).

The spelling of 14025130050 in words is "fourteen billion, twenty-five million, one hundred thirty thousand, fifty".