1411002224000 has 128 divisors (see below), whose sum is σ = 3565616652000. Its totient is φ = 555148032000.

The previous prime is 1411002223999. The next prime is 1411002224041. The reversal of 1411002224000 is 4222001141.

It is a tau number, because it is divible by the number of its divisors (128).

It is a super-3 number, since 3×1411002224000³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 1411002224000.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 253151 + ... + 1698849.

Almost surely, 2^{1411002224000} is an apocalyptic number.

1411002224000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1411002224000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1782808326000).

1411002224000 is an abundant number, since it is smaller than the sum of its proper divisors (2154614428000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1411002224000 is an equidigital number, since it uses as much as digits as its factorization.

1411002224000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1445789 (or 1445767 counting only the distinct ones).

The product of its (nonzero) digits is 128, while the sum is 17.

Adding to 1411002224000 its reverse (4222001141), we get a palindrome (1415224225141).

The spelling of 1411002224000 in words is "one trillion, four hundred eleven billion, two million, two hundred twenty-four thousand".