14113432120000 has 140 divisors (see below), whose sum is σ = 35129818372176. Its totient is φ = 5623903360000.

The previous prime is 14113432119973. The next prime is 14113432120091. The reversal of 14113432120000 is 2123431141.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 9849210 + ... + 11190790.

Almost surely, 2^{14113432120000} is an apocalyptic number.

14113432120000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 14113432120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17564909186088).

14113432120000 is an abundant number, since it is smaller than the sum of its proper divisors (21016386252176).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14113432120000 is an equidigital number, since it uses as much as digits as its factorization.

14113432120000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1341876 (or 1341851 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 14113432120000 its reverse (2123431141), we get a palindrome (14115555551141).

The spelling of 14113432120000 in words is "fourteen trillion, one hundred thirteen billion, four hundred thirty-two million, one hundred twenty thousand".