Base | Representation |
---|---|
bin | 1100111011010001110100… |
… | …0111001101110101011000 |
3 | 1212022201001000102110100220 |
4 | 3032310131013031311120 |
5 | 3330324233003312100 |
6 | 50121052030200040 |
7 | 2664551605016166 |
oct | 316643507156530 |
9 | 55281030373326 |
10 | 14212535213400 |
11 | 458a558676187 |
12 | 1716599353020 |
13 | 7c130c26b954 |
14 | 371c6728c236 |
15 | 199a79ab4aa0 |
hex | ced1d1cdd58 |
14212535213400 has 96 divisors (see below), whose sum is σ = 44185102962000. Its totient is φ = 3779149708800.
The previous prime is 14212535213389. The next prime is 14212535213423. The reversal of 14212535213400 is 431253521241.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 33726931 + ... + 34145730.
Almost surely, 214212535213400 is an apocalyptic number.
14212535213400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
14212535213400 is an abundant number, since it is smaller than the sum of its proper divisors (29972567748600).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14212535213400 is a wasteful number, since it uses less digits than its factorization.
14212535213400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 67873029 (or 67873020 counting only the distinct ones).
The product of its (nonzero) digits is 28800, while the sum is 33.
Adding to 14212535213400 its reverse (431253521241), we get a palindrome (14643788734641).
The spelling of 14212535213400 in words is "fourteen trillion, two hundred twelve billion, five hundred thirty-five million, two hundred thirteen thousand, four hundred".
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