Base | Representation |
---|---|
bin | 1101000110110110000111… |
… | …1011111100110100100010 |
3 | 1220000200222101010110201120 |
4 | 3101231201323330310202 |
5 | 3342103224121234100 |
6 | 50352235105313110 |
7 | 3015115263054402 |
oct | 321554173746442 |
9 | 56020871113646 |
10 | 14411258383650 |
11 | 4656864725287 |
12 | 1748bb9335796 |
13 | 806c8bba625b |
14 | 37b719960802 |
15 | 19ed0adc40a0 |
hex | d1b61efcd22 |
14411258383650 has 96 divisors (see below), whose sum is σ = 37622508820800. Its totient is φ = 3640589971200.
The previous prime is 14411258383591. The next prime is 14411258383663. The reversal of 14411258383650 is 5638385211441.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 14411258383593 and 14411258383602.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 80591340 + ... + 80769960.
It is an arithmetic number, because the mean of its divisors is an integer number (391901133550).
Almost surely, 214411258383650 is an apocalyptic number.
14411258383650 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
14411258383650 is an abundant number, since it is smaller than the sum of its proper divisors (23211250437150).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14411258383650 is a wasteful number, since it uses less digits than its factorization.
14411258383650 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 206964 (or 206959 counting only the distinct ones).
The product of its (nonzero) digits is 2764800, while the sum is 51.
The spelling of 14411258383650 in words is "fourteen trillion, four hundred eleven billion, two hundred fifty-eight million, three hundred eighty-three thousand, six hundred fifty".
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