Base | Representation |
---|---|
bin | 1100010010000111110… |
… | …1101011001001000000 |
3 | 202011200120101221011000 |
4 | 3010201331223021000 |
5 | 11424133420304440 |
6 | 240535343452000 |
7 | 21150231500406 |
oct | 3044175531100 |
9 | 664616357130 |
10 | 211023213120 |
11 | 81549114395 |
12 | 34a932b7000 |
13 | 16b8ccb35a5 |
14 | a2dc0b5476 |
15 | 575109b730 |
hex | 3121f6b240 |
211023213120 has 112 divisors (see below), whose sum is σ = 744443032320. Its totient is φ = 56272854528.
The previous prime is 211023213091. The next prime is 211023213139. The reversal of 211023213120 is 21312320112.
211023213120 is a `hidden beast` number, since 21 + 10 + 2 + 321 + 312 + 0 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a junction number, because it is equal to n+sod(n) for n = 211023213093 and 211023213102.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12203352 + ... + 12220631.
Almost surely, 2211023213120 is an apocalyptic number.
211023213120 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
211023213120 is an abundant number, since it is smaller than the sum of its proper divisors (533419819200).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
211023213120 is a wasteful number, since it uses less digits than its factorization.
211023213120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24424009 (or 24423993 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 211023213120 its reverse (21312320112), we get a palindrome (232335533232).
The spelling of 211023213120 in words is "two hundred eleven billion, twenty-three million, two hundred thirteen thousand, one hundred twenty".
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