Base | Representation |
---|---|
bin | 1000100111000000… |
… | …1101000100100000 |
3 | 12222001202210211100 |
4 | 2021300031010200 |
5 | 14213121140130 |
6 | 1021155114400 |
7 | 111162103503 |
oct | 21160150440 |
9 | 5861683740 |
10 | 2311115040 |
11 | a86622a33 |
12 | 545ba2a00 |
13 | 2aaa673c0 |
14 | 17cd2313a |
15 | d7d69c60 |
hex | 89c0d120 |
2311115040 has 144 divisors (see below), whose sum is σ = 8493416568. Its totient is φ = 568885248.
The previous prime is 2311115033. The next prime is 2311115047. The reversal of 2311115040 is 405111132.
It is an interprime number because it is at equal distance from previous prime (2311115033) and next prime (2311115047).
It can be written as a sum of positive squares in 4 ways, for example, as 2093611536 + 217503504 = 45756^2 + 14748^2 .
It is a tau number, because it is divible by the number of its divisors (144).
It is a super-2 number, since 2×23111150402 = 10682505456228403200, which contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is not an unprimeable number, because it can be changed into a prime (2311115047) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 43009 + ... + 80448.
Almost surely, 22311115040 is an apocalyptic number.
2311115040 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
2311115040 is an abundant number, since it is smaller than the sum of its proper divisors (6182301528).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2311115040 is a wasteful number, since it uses less digits than its factorization.
2311115040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 123491 (or 123480 counting only the distinct ones).
The product of its (nonzero) digits is 120, while the sum is 18.
The square root of 2311115040 is about 48074.0578690836. The cubic root of 2311115040 is about 1322.1290709928.
Adding to 2311115040 its reverse (405111132), we get a palindrome (2716226172).
It can be divided in two parts, 231 and 1115040, that added together give a triangular number (1115271 = T1493).
The spelling of 2311115040 in words is "two billion, three hundred eleven million, one hundred fifteen thousand, forty".
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