Base | Representation |
---|---|
bin | 1110000110010100001010… |
… | …11001100101101000100000 |
3 | 11001202212222010021020021120 |
4 | 13003022011121211220200 |
5 | 13030424240334120000 |
6 | 145534420325452240 |
7 | 6346625655012225 |
oct | 703120531455040 |
9 | 131685863236246 |
10 | 31003312020000 |
11 | 9973481420661 |
12 | 3588796571080 |
13 | 143b7a4938228 |
14 | 7927d561b94c |
15 | 38b7021b96a0 |
hex | 1c3285665a20 |
31003312020000 has 120 divisors (see below), whose sum is σ = 101697064284816. Its totient is φ = 8267549856000.
The previous prime is 31003312019969. The next prime is 31003312020019. The reversal of 31003312020000 is 2021330013.
It is a tau number, because it is divible by the number of its divisors (120).
It is a super-2 number, since 2×310033120200002 (a number of 28 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is an unprimeable number.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 258300934 + ... + 258420933.
Almost surely, 231003312020000 is an apocalyptic number.
31003312020000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
31003312020000 is an abundant number, since it is smaller than the sum of its proper divisors (70693752264816).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31003312020000 is an equidigital number, since it uses as much as digits as its factorization.
31003312020000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 516721900 (or 516721877 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 15.
Adding to 31003312020000 its reverse (2021330013), we get a palindrome (31005333350013).
The spelling of 31003312020000 in words is "thirty-one trillion, three billion, three hundred twelve million, twenty thousand".
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