Base | Representation |
---|---|
bin | 1110001101001111100010… |
… | …00010111011010100000100 |
3 | 11002121122100210012110001120 |
4 | 13012213301002323110010 |
5 | 13043324231323020400 |
6 | 150240023553353540 |
7 | 6403053362562564 |
oct | 706476102732404 |
9 | 132548323173046 |
10 | 31241341220100 |
11 | 9a55418727750 |
12 | 3606945b688b0 |
13 | 145807991746b |
14 | 7a0136252da4 |
15 | 3929d40ceca0 |
hex | 1c69f10bb504 |
31241341220100 has 144 divisors (see below), whose sum is σ = 99585361503936. Its totient is φ = 7498671680000.
The previous prime is 31241341220099. The next prime is 31241341220107. The reversal of 31241341220100 is 102214314213.
It is not an unprimeable number, because it can be changed into a prime (31241341220107) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 46533399 + ... + 47199998.
It is an arithmetic number, because the mean of its divisors is an integer number (691565010444).
Almost surely, 231241341220100 is an apocalyptic number.
31241341220100 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
31241341220100 is an abundant number, since it is smaller than the sum of its proper divisors (68344020283836).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31241341220100 is a wasteful number, since it uses less digits than its factorization.
31241341220100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 93733526 (or 93733519 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 31241341220100 its reverse (102214314213), we get a palindrome (31343555534313).
The spelling of 31241341220100 in words is "thirty-one trillion, two hundred forty-one billion, three hundred forty-one million, two hundred twenty thousand, one hundred".
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