Base | Representation |
---|---|
bin | 100011100110000111010000… |
… | …0011111001000001010001110 |
3 | 1112001121012201210212102221110 |
4 | 1013030032200133020022032 |
5 | 312014323344414104200 |
6 | 3025524503301512450 |
7 | 122643560245232403 |
oct | 10714164037101216 |
9 | 1461535653772843 |
10 | 313101513425550 |
11 | 90844673875333 |
12 | 2b149207412726 |
13 | 105924662b2a35 |
14 | 57462a08b82aa |
15 | 262e75002cb50 |
hex | 11cc3a07c828e |
313101513425550 has 96 divisors (see below), whose sum is σ = 779039957001600. Its totient is φ = 83219935190400.
The previous prime is 313101513425539. The next prime is 313101513425573. The reversal of 313101513425550 is 55524315101313.
It is a junction number, because it is equal to n+sod(n) for n = 313101513425499 and 313101513425508.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 124975509 + ... + 127456191.
It is an arithmetic number, because the mean of its divisors is an integer number (8114999552100).
Almost surely, 2313101513425550 is an apocalyptic number.
313101513425550 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 313101513425550, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (389519978500800).
313101513425550 is an abundant number, since it is smaller than the sum of its proper divisors (465938443576050).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
313101513425550 is a wasteful number, since it uses less digits than its factorization.
313101513425550 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2483458 (or 2483453 counting only the distinct ones).
The product of its (nonzero) digits is 135000, while the sum is 39.
Adding to 313101513425550 its reverse (55524315101313), we get a palindrome (368625828526863).
The spelling of 313101513425550 in words is "three hundred thirteen trillion, one hundred one billion, five hundred thirteen million, four hundred twenty-five thousand, five hundred fifty".
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