4331231130040 has 64 divisors (see below), whose sum is σ = 10363933591200. Its totient is φ = 1624387903488.

The previous prime is 4331231129989. The next prime is 4331231130041. The reversal of 4331231130040 is 400311321334.

It is a junction number, because it is equal to n+sod(n) for n = 4331231129987 and 4331231130014.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4331231130041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 29302509 + ... + 29449948.

Almost surely, 2^{4331231130040} is an apocalyptic number.

4331231130040 is a gapful number since it is divisible by the number (40) formed by its first and last digit.

It is an amenable number.

4331231130040 is an abundant number, since it is smaller than the sum of its proper divisors (6032702461160).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

4331231130040 is a wasteful number, since it uses less digits than its factorization.

4331231130040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 58752584 (or 58752580 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 4331231130040 its reverse (400311321334), we get a palindrome (4731542451374).

The spelling of 4331231130040 in words is "four trillion, three hundred thirty-one billion, two hundred thirty-one million, one hundred thirty thousand, forty".