Search a number
-
+
51125415000 = 2335411309851
BaseRepresentation
bin101111100111010011…
…111110110001011000
311212222000111011202220
4233213103332301120
51314201101240000
635253043024040
73456635600022
oct574723766130
9155860434686
1051125415000
111a755a66aa0
129aa996b020
134a89c7b76a
14268dda7012
1514e359b1a0
hexbe74fec58

51125415000 has 160 divisors (see below), whose sum is σ = 174235976640. Its totient is φ = 12394000000.

The previous prime is 51125414993. The next prime is 51125415007. The reversal of 51125415000 is 51452115.

It is an interprime number because it is at equal distance from previous prime (51125414993) and next prime (51125415007).

It is a super-2 number, since 2×511254150002 (a number of 22 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51125415007) by changing a digit.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 10075 + ... + 319925.

It is an arithmetic number, because the mean of its divisors is an integer number (1088974854).

Almost surely, 251125415000 is an apocalyptic number.

51125415000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 51125415000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (87117988320).

51125415000 is an abundant number, since it is smaller than the sum of its proper divisors (123110561640).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

51125415000 is a wasteful number, since it uses less digits than its factorization.

51125415000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 309891 (or 309872 counting only the distinct ones).

The product of its (nonzero) digits is 1000, while the sum is 24.

Adding to 51125415000 its reverse (51452115), we get a palindrome (51176867115).

The spelling of 51125415000 in words is "fifty-one billion, one hundred twenty-five million, four hundred fifteen thousand".

Divisors: 1 2 3 4 5 6 8 10 11 12 15 20 22 24 25 30 33 40 44 50 55 60 66 75 88 100 110 120 125 132 150 165 200 220 250 264 275 300 330 375 440 500 550 600 625 660 750 825 1000 1100 1250 1320 1375 1500 1650 1875 2200 2500 2750 3000 3300 3750 4125 5000 5500 6600 6875 7500 8250 11000 13750 15000 16500 20625 27500 33000 41250 55000 82500 165000 309851 619702 929553 1239404 1549255 1859106 2478808 3098510 3408361 3718212 4647765 6197020 6816722 7436424 7746275 9295530 10225083 12394040 13633444 15492550 17041805 18591060 20450166 23238825 27266888 30985100 34083610 37182120 38731375 40900332 46477650 51125415 61970200 68167220 77462750 81800664 85209025 92955300 102250830 116194125 136334440 154925500 170418050 185910600 193656875 204501660 232388250 255627075 309851000 340836100 387313750 409003320 426045125 464776500 511254150 580970625 681672200 774627500 852090250 929553000 1022508300 1161941250 1278135375 1549255000 1704180500 2045016600 2130225625 2323882500 2556270750 3408361000 4260451250 4647765000 5112541500 6390676875 8520902500 10225083000 12781353750 17041805000 25562707500 51125415000