Base | Representation |
---|---|
bin | 10111111000001111100100… |
… | …11010001001011110000000 |
3 | 20212220220121010021010000011 |
4 | 23330013302122021132000 |
5 | 23340311031241300100 |
6 | 303402440315234304 |
7 | 14026503536505364 |
oct | 1374076232113600 |
9 | 225826533233004 |
10 | 52510042134400 |
11 | 1580542493a5a4 |
12 | 5a8096aa48994 |
13 | 233b8a2755776 |
14 | cd76dcc8b2a4 |
15 | 610d901a2bba |
hex | 2fc1f2689780 |
52510042134400 has 96 divisors (see below), whose sum is σ = 130198432001400. Its totient is φ = 20925934663680.
The previous prime is 52510042134343. The next prime is 52510042134481. The reversal of 52510042134400 is 443124001525.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 29639922 + ... + 31361521.
Almost surely, 252510042134400 is an apocalyptic number.
52510042134400 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
52510042134400 is an abundant number, since it is smaller than the sum of its proper divisors (77688389867000).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
52510042134400 is a wasteful number, since it uses less digits than its factorization.
52510042134400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 61001736 (or 61001719 counting only the distinct ones).
The product of its (nonzero) digits is 19200, while the sum is 31.
Adding to 52510042134400 its reverse (443124001525), we get a palindrome (52953166135925).
The spelling of 52510042134400 in words is "fifty-two trillion, five hundred ten billion, forty-two million, one hundred thirty-four thousand, four hundred".
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