Base | Representation |
---|---|
bin | 10000010100001000101… |
… | …100000011100111010000 |
3 | 10222011211122002100002102 |
4 | 100110020230003213100 |
5 | 121332034322343440 |
6 | 2215012510335532 |
7 | 143666462504546 |
oct | 20241054034720 |
9 | 3864748070072 |
10 | 1121132231120 |
11 | 3a2518a0a010 |
12 | 161348aba5a8 |
13 | 81950c0a245 |
14 | 3c397cbbd96 |
15 | 1e26ad1cb15 |
hex | 10508b039d0 |
1121132231120 has 80 divisors (see below), whose sum is σ = 2871753696000. Its totient is φ = 403647936000.
The previous prime is 1121132231117. The next prime is 1121132231123. The reversal of 1121132231120 is 211322311211.
It is an interprime number because it is at equal distance from previous prime (1121132231117) and next prime (1121132231123).
It is a tau number, because it is divible by the number of its divisors (80).
It is a super-2 number, since 2×11211322311202 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a junction number, because it is equal to n+sod(n) for n = 1121132231092 and 1121132231101.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1121132231123) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6218120 + ... + 6395879.
It is an arithmetic number, because the mean of its divisors is an integer number (35896921200).
Almost surely, 21121132231120 is an apocalyptic number.
1121132231120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1121132231120 is an abundant number, since it is smaller than the sum of its proper divisors (1750621464880).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1121132231120 is a wasteful number, since it uses less digits than its factorization.
1121132231120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12614124 (or 12614118 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 1121132231120 its reverse (211322311211), we get a palindrome (1332454542331).
It can be divided in two parts, 1 and 121132231120, that added together give a palindrome (121132231121).
The spelling of 1121132231120 in words is "one trillion, one hundred twenty-one billion, one hundred thirty-two million, two hundred thirty-one thousand, one hundred twenty".
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