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11323312440 = 23351167712671
BaseRepresentation
bin10101000101110110…
…00000100100111000
31002020010210212112020
422202323000210320
5141142231444230
65111333514440
7550413365466
oct124273004470
932203725466
1011323312440
114890795260
1222401a2a20
1310b5bc849b
14795bd1836
15464155810
hex2a2ec0938

11323312440 has 128 divisors (see below), whose sum is σ = 37115781120. Its totient is φ = 2740774400.

The previous prime is 11323312387. The next prime is 11323312463. The reversal of 11323312440 is 4421332311.

It is a happy number.

It is a super-2 number, since 2×113233124402 (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a self number, because there is not a number n which added to its sum of digits gives 11323312440.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 887305 + ... + 899975.

It is an arithmetic number, because the mean of its divisors is an integer number (289967040).

Almost surely, 211323312440 is an apocalyptic number.

11323312440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11323312440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18557890560).

11323312440 is an abundant number, since it is smaller than the sum of its proper divisors (25792468680).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11323312440 is a wasteful number, since it uses less digits than its factorization.

11323312440 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13373 (or 13369 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 11323312440 its reverse (4421332311), we get a palindrome (15744644751).

It can be divided in two parts, 1132331 and 2440, that added together give a triangular number (1134771 = T1506).

The spelling of 11323312440 in words is "eleven billion, three hundred twenty-three million, three hundred twelve thousand, four hundred forty".

Divisors: 1 2 3 4 5 6 8 10 11 12 15 20 22 24 30 33 40 44 55 60 66 88 110 120 132 165 220 264 330 440 660 677 1320 1354 2031 2708 3385 4062 5416 6770 7447 8124 10155 12671 13540 14894 16248 20310 22341 25342 27080 29788 37235 38013 40620 44682 50684 59576 63355 74470 76026 81240 89364 101368 111705 126710 139381 148940 152052 178728 190065 223410 253420 278762 297880 304104 380130 418143 446820 506840 557524 696905 760260 836286 893640 1115048 1393810 1520520 1672572 2090715 2787620 3345144 4181430 5575240 8362860 8578267 16725720 17156534 25734801 34313068 42891335 51469602 68626136 85782670 94360937 102939204 128674005 171565340 188721874 205878408 257348010 283082811 343130680 377443748 471804685 514696020 566165622 754887496 943609370 1029392040 1132331244 1415414055 1887218740 2264662488 2830828110 3774437480 5661656220 11323312440