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114042132000 = 2532533167837
BaseRepresentation
bin110101000110101110…
…0001101011000100000
3101220100210101120001200
41222031130031120200
53332024241211000
6124220142401200
711145033061566
oct1521534153040
9356323346050
10114042132000
11444018a0775
121a128590200
13a9a5a806a4
14573bd83a36
152e76de1500
hex1a8d70d620

114042132000 has 144 divisors (see below), whose sum is σ = 404735654232. Its totient is φ = 30411225600.

The previous prime is 114042131993. The next prime is 114042132007. The reversal of 114042132000 is 231240411.

114042132000 is a `hidden beast` number, since 1 + 1 + 40 + 421 + 3 + 200 + 0 = 666.

It is an interprime number because it is at equal distance from previous prime (114042131993) and next prime (114042132007).

It can be written as a sum of positive squares in 4 ways, for example, as 8076257424 + 105965874576 = 89868^2 + 325524^2 .

It is a tau number, because it is divible by the number of its divisors (144).

It is a super-2 number, since 2×1140421320002 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is not an unprimeable number, because it can be changed into a prime (114042132007) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1547919 + ... + 1619918.

Almost surely, 2114042132000 is an apocalyptic number.

114042132000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

114042132000 is an abundant number, since it is smaller than the sum of its proper divisors (290693522232).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

114042132000 is a wasteful number, since it uses less digits than its factorization.

114042132000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3167868 (or 3167847 counting only the distinct ones).

The product of its (nonzero) digits is 192, while the sum is 18.

Adding to 114042132000 its reverse (231240411), we get a palindrome (114273372411).

The spelling of 114042132000 in words is "one hundred fourteen billion, forty-two million, one hundred thirty-two thousand".

Divisors: 1 2 3 4 5 6 8 9 10 12 15 16 18 20 24 25 30 32 36 40 45 48 50 60 72 75 80 90 96 100 120 125 144 150 160 180 200 225 240 250 288 300 360 375 400 450 480 500 600 720 750 800 900 1000 1125 1200 1440 1500 1800 2000 2250 2400 3000 3600 4000 4500 6000 7200 9000 12000 18000 36000 3167837 6335674 9503511 12671348 15839185 19007022 25342696 28510533 31678370 38014044 47517555 50685392 57021066 63356740 76028088 79195925 95035110 101370784 114042132 126713480 142552665 152056176 158391850 190070220 228084264 237587775 253426960 285105330 304112352 316783700 380140440 395979625 456168528 475175550 506853920 570210660 633567400 712763325 760280880 791959250 912337056 950351100 1140421320 1187938875 1267134800 1425526650 1520561760 1583918500 1900702200 2280842640 2375877750 2534269600 2851053300 3167837000 3563816625 3801404400 4561685280 4751755500 5702106600 6335674000 7127633250 7602808800 9503511000 11404213200 12671348000 14255266500 19007022000 22808426400 28510533000 38014044000 57021066000 114042132000