Base | Representation |
---|---|
bin | 10001011110101101101… |
… | …101101100001010010000 |
3 | 11020211112102010021222100 |
4 | 101132231231230022100 |
5 | 124140034314430222 |
6 | 2315454533440400 |
7 | 152533053115314 |
oct | 21365555541220 |
9 | 4224472107870 |
10 | 1201210311312 |
11 | 4234809a5980 |
12 | 174976aa0100 |
13 | 8937327c64b |
14 | 421d317db44 |
15 | 213a60b14ac |
hex | 117adb6c290 |
1201210311312 has 120 divisors (see below), whose sum is σ = 3679049713248. Its totient is φ = 362840025600.
The previous prime is 1201210311307. The next prime is 1201210311347. The reversal of 1201210311312 is 2131130121021.
1201210311312 is a `hidden beast` number, since 1 + 20 + 1 + 21 + 0 + 311 + 312 = 666.
It is a super-2 number, since 2×12012103113122 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 715614 + ... + 1707197.
Almost surely, 21201210311312 is an apocalyptic number.
1201210311312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1201210311312 is an abundant number, since it is smaller than the sum of its proper divisors (2477839401936).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1201210311312 is a wasteful number, since it uses less digits than its factorization.
1201210311312 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2423149 (or 2423140 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 18.
Adding to 1201210311312 its reverse (2131130121021), we get a palindrome (3332340432333).
The spelling of 1201210311312 in words is "one trillion, two hundred one billion, two hundred ten million, three hundred eleven thousand, three hundred twelve".
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